To avoid each other, each of the three teams (let's call them A, B, and C) must be in a different match. Team A is placed in a match. There are 7 available opponents. To avoid B and C, A must be paired with one of the 5 other teams (D, E, F, G, or H) = 5/7.
Team B is then placed in a match. There are now 5 remaining teams. To avoid Team C, B must be paired with one of the 4 other remaining teams (excluding C) = 4/5.
Team C and the remaining teams will then be paired automatically in the remaining slots. The probability is calculated by multiplying these individual chances: 5/7 x 4/5 = 4/7 = 57.14%
Answer: The chances of three specific teams out of eight avoiding each other in a tournament draw (such as a quarter-final) are 4/7 which is approximately 57.14%.
Posted By: Cellophane Flowers, Feb 3, 09:07:07
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